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Geometry CAT 2025 Slot 3 Actual Questions

Visual lens G Strategy (Concept of similarities) | Easy

In a triangle ABC, AB=AC=12 cm and D is a point on side BC such that AD= 8 cm. If AD is extended to point E such that angle ACB = angle AEB , then length in cm of AE is :

1.16

2.18

3.14

4.20

Answer & Explanation

Based on the information in the question triangle ABD ≈ triangle AEB , Thus :

AB/AE = AD/AB ,

12/AE = 8/12 = 2/3

Only option 2 satisfies the condition. Thus option 2 is the answer

Visual G Strategy | Triplets + Area of Triangles | Moderate

A triangle ABC is formed with AB = AC  = 50 cm and BC = 80 cm. Then, the length, in cm , of all three altitudes of the triangle ABC is….. …

Solution & Explanation

Give AB = AC = 50 cm , BC = 80 cm

 The altitude from A to BC

Half of BC: 80 / 2 = 40 cm

Use Pythagoras’ theorem to find altitude h:

h² + 40² = 50²

h² + 1600 = 2500

h² = 900 , h = 30 cm

Altitude from A to BC = 30 cm

The altitudes from B and C

Area of the triangle using the altitude from A:

Area = (1/2) × 80 × 30 = 1200 cm²

Using area to find the altitude from B:

1200 = (1/2) × 50 × h

h = 1200 / 25 = 48 cm

Altitude from B to AC = 48 cm

Altitude from C to AB = 48 cm

Sum = 30 + 48 + 48 = 126

Answer 126

Visual G Strategy | Cyclic quadrilateral+ Area of trapezium | Moderate

ABCD is a trapezium in which AB is parallel to DC and AD is perpendicular to AB and AB = 3DC. If a circle inscribed in a trapezium touching all the sides has a radius 3cm , then the area in sq cm , of the trapezium is :

1.48

2.36√2

3.54

4.30√3

Solution & Explanation

Given:

Let the trapezium be ABCD.

AB || DC (The parallel sides are the bases).

AD perpendicular to AB (The trapezium is a right-angle trapezium). AB = 3DC. If AB = x , then DC = 3x

The circle inscribed in the trapezium has a radius r = 3cm

Height = 2r = 2 × 3 = 6cm

For cyclic quadrilateral Sum of parallel sides= Sum of non-parallel sides

AB + DC = AD + BC

3x + x = 6 + BC

BC = 4x – 6  —– I

In Triangle AEB with base BE , height CE and hypotenuse BC

BE = DC – AB = 3x – x = 2x , CE = 6cm , BC = 4x – 6

Using Pythagoras:

(2x)² + (6)² = (4x – 6)²

On solving we have x = 4cm

Area of trapezium = ½ * (AB + DC) × AD

= ½ .(4x) .6 = 48cm² ,  This option 1 is the answer

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