CAT CET SNAP NMAT CMAT XAT

CAT 2025 Slot 2 Vedic Patterns Quant G Strategy

Vedic Patterns G Strategy | Quadratic Equations | Hard

    If m and n are integers such that (m + 2n)(2m + n) = 27,
    then the maximum possible value of 2m − 3n is ___

    Answer & Explanation

    Given: (m + 2n)(2m + n) = 27

    Since m and n are integers, (m + 2n) and (2m + n) must be integer factors of 27.

    Possible factor pairs (m + 2n, 2m + n) are:
    (1, 27), (3, 9), (9, 3), (27, 1),
    (−1, −27), (−3, −9), (−9, −3), (−27, −1)

    We now solve each pair as a system: m + 2n = A; 2m + n = B

    From these:
    Multiply first equation by 2: 2m + 4n = 2A
    Subtract from second: (2m + n) − (2m + 4n) = B − 2A
    ⇒ −3n = B − 2A ⇒ n = (2A − B) / 3
    Then m = A − 2n

    m + 2n2m + nn = (2A − B)/3m = A − 2n2m − 3nValid / Reject
    127(2 − 27)/3 = −25/3Reject
    39(6 − 9)/3 = −13 − 2(−1) = 513Valid
    93(18 − 3)/3 = 59 − 10 = −1−17Valid
    271(54 − 1)/3 = 53/3Reject
    −1−27(−2 + 27)/3 = 25/3Reject
    −3−9(−6 + 9)/3 = 1−3 − 2 = −5−13Valid
    −9−3(−18 + 3)/3 = −5−9 + 10 = 117Valid
    −27−1(−54 + 1)/3 = −53/3Reject

    Maximum possible valid value of 2m − 3n = 17

    Vedic Patterns G Strategy | Moderate

    Suppose a, b, c are three distinct natural numbers, such that 3ac = 8(a + b).
    Then, the smallest possible value of 3a + 2b + c is _______

    Answer & Explanation

    Final Answer: 12

    Given: 3ac = 8(a + b) ⇒ 8b = 3ac − 8a ⇒ b = (3ac/8) − a

    Since a, b, c are natural numbers, 3ac must be divisible by 8.

    Now try small values of a (since we want the minimum value of 3a + 2b + c).

    Try a = 1

    Then 3c must be divisible by 8 ⇒ c = 8

    b = (3×1×8)/8 − 1 = 3 − 1 = 2

    Value = 3a + 2b + c = 3 + 4 + 8 = 15

    Try a = 2

    Then 6c divisible by 8 ⇒ c = 4 is the smallest possible

    b = (3×2×4)/8 − 2 = 3 − 2 = 1

    Here a, b, c = 2, 1, 4 are distinct natural numbers

    Value = 3a + 2b + c = 6 + 2 + 4 = 12

    Try a = 3

    Then 9c divisible by 8 ⇒ c = 8

    b = (3×3×8)/8 − 3 = 9 − 3 = 6

    Value = 9 + 12 + 8 = 29 (larger)

    Hence the smallest possible value occurs at a = 2, b = 1, c = 4

    Register to Attend Free Workshop by Rav Sir

    example, category, and, terms