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CAT 2024 Slot 3 Vedic Tables G Strategy

The number of distinct integer solutions (x, y) of the equation |x + y| + |x – y| = 2, is

Solution

Since two absolute values are added, for the equation to be true we can have three combinations of \(|x + y|, |x – y|\): \[ \{2, 0\}, \{0, 2\}, \{1, 1\} \]

Cases and Corresponding Solutions:

Case Conditions Solution(s)
Case 1 \( x + y = 2 \) and \( x – y = 0 \) \( \{x, y\} = \{1, 1\} \)
Case 2 \( x + y = -2 \) and \( x – y = 0 \) \( \{x, y\} = \{-1, -1\} \)
Case 3 \( x + y = 0 \) and \( x – y = 2 \) \( \{x, y\} = \{1, -1\} \)
Case 4 \( x + y = 0 \) and \( x – y = -2 \) \( \{x, y\} = \{-1, 1\} \)
Case 5 \( x + y = 1 \) and \( x – y = 1 \) \( \{x, y\} = \{1, 0\} \)
Case 6 \( x + y = 1 \) and \( x – y = -1 \) \( \{x, y\} = \{0, 1\} \)
Case 7 \( x + y = -1 \) and \( x – y = 1 \) \( \{x, y\} = \{0, -1\} \)
Case 8 \( x + y = -1 \) and \( x – y = -1 \) \( \{x, y\} = \{-1, 0\} \)

✅ Hence, there are 8 distinct integer solutions for \(\{x, y\}\).

If 10^68 is divided by 13, the remainder is
1) 8 2) 9 3) 4 4) 5

Solution

Let’s solve 10^68 ÷ 13 — find the remainder using the cycle method:


Step 1: Find powers of 10 modulo 13

  • 10¹ mod 13 = 10
  • 10² mod 13 = (10 × 10) mod 13 = 100 mod 13
    100 ÷ 13 = 7 remainder 9 → 10² mod 13 = 9
  • 10³ mod 13 = (10² × 10) mod 13 = (9 × 10) mod 13 = 90 mod 13
    90 ÷ 13 = 6 remainder 12 → 10³ mod 13 = 12
  • 10⁴ mod 13 = (12 × 10) mod 13 = 120 mod 13
    120 ÷ 13 = 9 remainder 3 → 10⁴ mod 13 = 3
  • 10⁵ mod 13 = (3 × 10) mod 13 = 30 mod 13
    30 ÷ 13 = 2 remainder 4 → 10⁵ mod 13 = 4
  • 10⁶ mod 13 = (4 × 10) mod 13 = 40 mod 13
    40 ÷ 13 = 3 remainder 1 → 10⁶ mod 13 = 1

✅ The cycle length is 6:
10^6 mod 13 = 1


Step 2: Find position in cycle

10^68 mod 13 = 10^(68 mod 6) mod 13

68 ÷ 6 = 11 remainder 2

So 10^68 mod 13 = 10² mod 13 = 9


✅ Final answer:

👉 The remainder is 9

Correct option: 2) 9


Find the number of all positive integers up to 500 with non-repeating digits.

Type of Number Digit Positions Choices at Each Step Reasoning Count
1-digit _ 1-9 → 9 choices Any digit 1-9 is valid 9
2-digit Tens digit 1-9 → 9 choices Tens digit can’t be 0 81
Units digit 0-9 except tens digit → 9 choices Can’t repeat tens digit
3-digit (100-499) Hundreds digit 1-4 → 4 choices First digit ≤ 4 so number ≤ 499 288
Tens digit 0-9 except hundreds digit → 9 choices Must differ from hundreds digit
Units digit 0-9 except hundreds & tens digit → 8 choices Must differ from both

Final Total: 9 (1-digit) + 81 (2-digit) + 288 (3-digit) = 378

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